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For the rules of piraten kapern, see <b>[[Gamehelppiratenkapern|GameHelpPiratenKapern]]</b> | |||
== Probabilities == | |||
{{infoBoxes | title1=Binomial formula | body1=<b></b> | |||
<u> n! </u> × pᵏ(1 − p)ⁿ⁻ᵏ | |||
k!(n-k)! | |||
n: number of trails (dice thrown) | |||
k: number of successes (dice with a face value) | |||
p: probability of success (of a die face value) | |||
| title2=Example | body2= | |||
Probability of throwing '''3'''{{whiteDie|4}} with '''5''' dice: | |||
<u> 5! </u> × (⅙)³ × (1 − ⅙)⁵⁻³ | |||
3!(5-3)! | |||
= <u> 5×4×3×2×1 </u> × (⅙)³ × (⅚)² | |||
3×2×1 × 2×1 | |||
= 10 × (⅙)³ × (⅚)² | |||
≈ 0.0321 or 3.21% | |||
}} | |||
=== 2 dice === | |||
{|class="wikitable" style="width:auto;" | |||
|+Probabilities of throwing X skulls with two six-sided dice | |||
!In words | |||
!In maths | |||
!Percentage | |||
|- | |||
|Probability of no skulls | |||
|P(X = 0) = (⅚)² | |||
|≈ 69.4% | |||
|- | |||
|Probability of one skull | |||
|P(X = 1) = 2 × (⅙) × (⅚) | |||
|≈ 27.8% | |||
|- | |||
|Probability of two skulls | |||
|P(X = 2) = (⅙)² | |||
|≈ 2.78% | |||
|} | |||
=== 8 dice === | |||
{|class="wikitable" style="width:auto;" | |||
|+Probabilities of throwing X skulls with eight six-sided dice | |||
!In words | |||
!In maths | |||
!Percentage | |||
|- | |||
|Probability of no skulls | |||
|P(X = 0) = (⅚)⁸ | |||
|≈ 23.3% | |||
|- | |||
|Probability of one skull | |||
|P(X = 1) = 8 × (⅙) × (⅚)⁷ | |||
|≈ 37.2% | |||
|- | |||
|Probability of two skulls | |||
|P(X = 2) = 28 × (⅙)² × (⅚)⁶ | |||
|≈ 26.0% | |||
|- | |||
|Probability of three skulls | |||
|P(X = 3) = 56 × (⅙)³ × (⅚)⁵ | |||
|≈ 10.4% | |||
|- | |||
|Probability of four skulls | |||
|P(X = 4) = 70 × (⅙)⁴ × (⅚)⁴ | |||
|≈ 2.60% | |||
|} | |||
{|class="wikitable" style="width:auto;" | |||
|+Probabilities of throwing X ''or more'' skulls with eight six-sided dice | |||
!In words | |||
!In maths | |||
!Percentage | |||
|- | |||
|Probability of one ''or more'' skulls | |||
|P(X ≥ 1) | |||
= 1 − P(X = 0) | |||
= 1 − (⅚)⁸ | |||
|≈ 76.7% | |||
|- | |||
|Probability of two ''or more'' skulls | |||
|P(X ≥ 2) | |||
= 1 − [ P(X = 0) + P(X = 1) ] | |||
= 1 − [ (⅚)⁸ + 8 × (⅙) × (⅚)⁷ ] | |||
|≈ 39.5% | |||
|- | |||
|Probability of three ''or more'' skulls | |||
|P(X ≥ 3) | |||
= 1 − [ P(X = 0) + P(X = 1) + P(X = 2) ] | |||
= 1 − [ (⅚)⁸ + 8 × (⅙) × (⅚)⁷ + 28 × (⅙)² × (⅚)⁶ ] | |||
|≈ 13.5% | |||
|- | |||
|Probability of four ''or more'' skulls | |||
|P(X ≥ 4) | |||
= 1 − [ P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) ] | |||
= 1 − [ (⅚)⁸ + 8 × (⅙) × (⅚)⁷ + 28 × (⅙)² × (⅚)⁶ + 56 × (⅙)³ × (⅚)⁵ ] | |||
|≈ 3.07% | |||
|} |
Latest revision as of 21:24, 12 February 2024
For the rules of piraten kapern, see GameHelpPiratenKapern
Probabilities
Binomial formula
n! × pᵏ(1 − p)ⁿ⁻ᵏ k!(n-k)!
n: number of trails (dice thrown) k: number of successes (dice with a face value)p: probability of success (of a die face value)
Example
Probability of throwing 3
5! × (⅙)³ × (1 − ⅙)⁵⁻³ 3!(5-3)!
= 5×4×3×2×1 × (⅙)³ × (⅚)² 3×2×1 × 2×1
= 10 × (⅙)³ × (⅚)²≈ 0.0321 or 3.21% with 5 dice:
2 dice
In words | In maths | Percentage |
---|---|---|
Probability of no skulls | P(X = 0) = (⅚)² | ≈ 69.4% |
Probability of one skull | P(X = 1) = 2 × (⅙) × (⅚) | ≈ 27.8% |
Probability of two skulls | P(X = 2) = (⅙)² | ≈ 2.78% |
8 dice
In words | In maths | Percentage |
---|---|---|
Probability of no skulls | P(X = 0) = (⅚)⁸ | ≈ 23.3% |
Probability of one skull | P(X = 1) = 8 × (⅙) × (⅚)⁷ | ≈ 37.2% |
Probability of two skulls | P(X = 2) = 28 × (⅙)² × (⅚)⁶ | ≈ 26.0% |
Probability of three skulls | P(X = 3) = 56 × (⅙)³ × (⅚)⁵ | ≈ 10.4% |
Probability of four skulls | P(X = 4) = 70 × (⅙)⁴ × (⅚)⁴ | ≈ 2.60% |
In words | In maths | Percentage |
---|---|---|
Probability of one or more skulls | P(X ≥ 1)
= 1 − P(X = 0) = 1 − (⅚)⁸ |
≈ 76.7% |
Probability of two or more skulls | P(X ≥ 2)
= 1 − [ P(X = 0) + P(X = 1) ] = 1 − [ (⅚)⁸ + 8 × (⅙) × (⅚)⁷ ] |
≈ 39.5% |
Probability of three or more skulls | P(X ≥ 3)
= 1 − [ P(X = 0) + P(X = 1) + P(X = 2) ] = 1 − [ (⅚)⁸ + 8 × (⅙) × (⅚)⁷ + 28 × (⅙)² × (⅚)⁶ ] |
≈ 13.5% |
Probability of four or more skulls | P(X ≥ 4)
= 1 − [ P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) ] = 1 − [ (⅚)⁸ + 8 × (⅙) × (⅚)⁷ + 28 × (⅙)² × (⅚)⁶ + 56 × (⅙)³ × (⅚)⁵ ] |
≈ 3.07% |